\(\cos(A+B)\cos(A-B)\)
=\((cosAcosB-sinAsinB)(cosAcosB+sinAsinB)\)
=\(\cos^{2}A\cos^{2}B-\sin^{2}A\sin^{2}B\)
=\((1-\sin^{2}A)(1-\sin^{2}B)-\sin^{2}A\sin^{2}A\)
=\(1-\sin^{2}A-\sin^{2}B+\sin^{2}A\sin^{2}B-\sin^{2}A\sin^{2}B\)
=\(\cos^{2}A-\sin^{2}B\)
OR \(\cos^{2}B-\sin^{2}A\)
\(\sin(A+B)\sin(A-B)\)
=\((sinAcosB+cosAsinB)(sinAcosB-cosAsinB)\)
=\((sinAcosB)^2-(cosAsinB)^2\)
=\(\sin^{2}A\cos^{2}B-\cos^{2}A\sin^{2}B\)
=\(\sin^{2}A(1-\sin^{2}B)-(1-\sin^{2}A)\sin^{2}B\)
=\(\sin^{2}A-\sin^{2}A\sin^{2}B-\sin^{2}B+\sin^{2}A\sin^{2}B\)
=\(\sin^{2}A-\sin^{2}B\)
=\((1-\cos^{2}A)-(1-\cos^{2}B)\)
=\(\cos^{2}B-\cos^{2}A\)
Thus \(\sin(A+B)\sin(A-B)\)
=\(\sin^{2}A-\sin^{2}B\)
or \(\cos^{2}B-\cos^{2}A\)