Problem based on conductance electrolytic solution

Problem based on conductance electrolytic solution

Q . The cell constant of a conductivity cell is 0.1 cm⁻¹. The concentration of the electrolyte is 0.1 M.
Find:
i) Conductance
ii) Specific conductance (κ)
iii) Molar conductance (Λ_m)

Ans:

Given:

• Cell constant (G_*) = 0.1 cm⁻¹
• Concentration (C) = 0.1 M
• Resistance (R) = 50 Ω

i) Conductance (G):
G = 1 / R = 1 / 50 = 0.02 S

ii) Specific conductance (κ):
κ = G × Cell constant = 0.02 × 0.1 = 0.002 S cm⁻¹

iii) Molar conductance (Λ_m):
Λ_m = (κ × 1000) / C = (0.002 × 1000) / 0.1 = 20 S cm² mol⁻¹