Show that, for any integer n
\(\cos (n \pi + \alpha)\)=\((-1)^{n}\cos \alpha\)
Solution:
Case I
When n be an even integer
n=2m, where m is any integer
\(\cos (n \pi + \alpha)\)
=\(\cos (2m \pi + \alpha)\)
In first quardent value of \(\cos\) is positive
=+ \(\cos \alpha\)...(1)
Case II
When n is an odd integer
n=2m+1, where m is any integer
\(\cos (n \pi + \alpha)\)
=\(\cos \left[(2m+1) \pi + \alpha\right]\)
In third quardent value of \(\cos\) is positive
=- \(\cos \alpha\)...(2)
From (1) and (2) we have
\(\cos (n \pi + \alpha)\)=\((-1)^{n}\cos \alpha\)
for all \(n \in Z\)