i) Find the zeroes of the quadratic polynomial x² - x - 6 and verify the relationship between zeroes and coefficients of x.
Given polynomial: x² - x - 6 To find the zeroes, factor the polynomial: x² - x - 6 = (x - 3)(x + 2) The roots of the equation are x = 3 and x = -2. Their sum is 3 + (–2) = 1, and their product is 3 × (–2) = –6 From the polynomial: ax² + bx + c → a = 1, b = -1, c = -6 Sum of zeroes = -b/a = -(-1)/1 = 1 ✔ Product of zeroes = c/a = -6/1 = -6 ✔ So, the connection between the zeroes and the polynomial's coefficients holds true.
ii) Find the quadratic polynomial where sum of zeroes = 3 and product = -√2 respectively.
Let α and β be the zeroes. Given: Sum (α + β) = 3 Product (α × β) = -√2 Quadratic polynomial = x² - (sum)x + product = x² - 3x - √2
iii) Find the cubic polynomial where three zeroes are 3, -1, and 2.
Let the zeroes be 3, -1, and 2. Cubic polynomial = (x - 3)(x + 1)(x - 2) Start by multiplying (x - 3) and (x + 1): (x - 3)(x + 1) = x² - 2x - 3 Next, multiply this result by (x - 2): (x² - 2x - 3)(x - 2) = x³ - 2x² - 3x - 2x² + 4x + 6 = x³ - 4x² + x + 6 Final polynomial: x³ - 4x² + x + 6