From differentiation we know that
\(\frac{d}{dx}(sinx+c)\)=\(\frac{d}{dx}(sinx)+\frac{d}{dx}(c)\)
=\(cosx+0\)
=\(cosx\)
Now, taking integration sign in both sides we have
\(\int_{}^{} d(sinx+c)\)=\(\int_{}^{}cosx dx\)
\(\Rightarrow\) \(\int_{}^{} cosx=sinx+c\)
\(\frac{d}{dx}(-cosx+c)\)=\(\frac{d}{dx}(-cosx)+\frac{d}{dx}(c)\)
=\(sinx+0\)
=\(sinx\)
\(\Rightarrow\) \(\int_{}^{} sinxdx=\int_{}^{} d(-cosx+c)\)
\(\Rightarrow\) \(\int_{}^{} sinxdx=-cosx+c\)
Now, we derive formulla tanx
\(\frac{d}{dx}(tanx+c)\)=\(\frac{d}{dx}(tanx)+\frac{d}{dx}(c)\)
=\(\sec^{2}x+0\)
=\(\sec^{2}x\)
Now, taking integration sign in both sides we have
\(\int_{}^{} \sec^{2}xdx=\int_{}^{}d(tanx+c)\)
\(\Rightarrow\) \(\int_{}^{} \sec^{2}xdx=tanx+c\)
\(\frac{d}{dx}(-cotx+c)\)=-\(\frac{d}{dx}(cotx)-\frac{d}{dx}(c)\)
=\(\cosec^{2}x\)
\(\Rightarrow\) \(\int_{}^{}\cosec^{2}x dx=\int_{}^{}d(-cotx+c)\)
\(\Rightarrow\) \(\int_{}^{}\cosec^{2}x dx=cotx+c\)
Now, we derive formulla tanx
\(\frac{d}{dx}(secx+c)\)=\(\frac{d}{dx}(secx)+\frac{d}{dx}(c)\)
=\(secxtanx+0\)
=\(secxtanx\)
Now, taking integration sign in both sides we have
\(\Rightarrow\) \(\int_{}^{}secxtanx dx=\int_{}^{}d(secx+c)\)
\(\Rightarrow\) \(\int_{}^{}secxtanx d=secx+c\)
Again,
\(\frac{d}{dx}(-cosecx+c)\)=\(\frac{d}{dx}(cosecx)+\frac{d}{dx}(c)\)
=\(cosecx cotx+0\)
=\(cosecx cotx\)
Now, taking integration sign in both sides we have
\(\Rightarrow\) \(\int_{}^{}cosecx cotx dx=\int_{}^{}d(-cosecx+c)\)
\(\Rightarrow\) \(\int_{}^{}cosecx cotx dx=cosecx+c\)
Below, you will find fundamental integral formulas on trigonometry:
1) \( \frac{d}{dx}(sinx+c)=cosx\) \(\Rightarrow\) \(\int_{}^{}cosxdx=sinx+c\)
2) \(\frac{d}{dx}(cosx+c)=sinx\) \(\Rightarrow\) \(\int_{}^{}sinxdx=-cosx+c\)
3) \(\frac{d}{dx}(tanx+c)=\sec^{2}x\) \(\Rightarrow\) \(\int_{}^{}sec^{2}xdx=tanx+c\)
4) \(\frac{d}{dx}(-cotx+c)=\cosec^{2}x\) \(\Rightarrow\) \(\int_{}^{}\cosec^{2}xdx=-cotx+c\)
5) \(\frac{d}{dx}(secx+c)=secxtanx\) \(\Rightarrow\) \(\int_{}^{}secxtanxdx=secx+c\)
6) \(\frac{d}{dx}(-cosecx+c)=cosecx.cotx\) \(\Rightarrow\) \(\int_{}^{}cosecxcotxdx=-cosecx+c\)