If you are given a polynomial and some of its zeroes, you can use that information to find the remaining zeroes. Here’s how the method works using this polynomial:
P(x) = 2x⁴ - 3x³ - 3x² + 6x - 2
It is known that √2 and −√2 are two of the polynomial’s zeroes.
Since √2 and −√2 are zeroes, their corresponding factor is:
(x - √2)(x + √2) = x² - 2
We now divide P(x) by x² - 2 using polynomial division (or synthetic division if applicable):
Divide:
P(x) = 2x⁴ - 3x³ - 3x² + 6x - 2
By: x² - 2
Using polynomial division (or long division), we get:
Quotient: 2x² - 3x - 1
Next, we factor the obtained quadratic expression:
2x² - 3x - 1
To factor this expression, we can apply either the method of splitting the middle term or use the quadratic formula.
2x² - 3x - 1 = (2x + 1)(x - 1)
The zeroes of the polynomial are the values of x that make each factor zero:
Given two zeroes of a polynomial, we factored the corresponding quadratic and divided the original polynomial by it. We then factored the resulting quotient to find all zeroes. Hence, the polynomial P(x) = 2x⁴ - 3x³ - 3x² + 6x - 2 has the following zeroes:
{√2, −√2, −1/2, 1}