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Mathematics

Eleven Standard >> tan and cot formula of compound angles

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tan and cot formula of compound angles:

 

Derive the formula of \(\tan(A+B)\)

\(\tan(A+B)=\frac{\sin(A+B)}{\cos(A+B)}\)
         =\(\frac{\sin A\cos B+\cos A\sin B}{\cos A\cos B-\sin A\sin B}\)
         Divide numerator and denominator by \(\cos A\cos B\) we get

\(\tan(A+B)=\frac{\tan A +\tan B}{1-\tan A\tan B}\)

Derive the formula of \(\tan(A-B)\)

\(\tan(A-B)=\frac{\sin(A-B)}{\cos(A-B)}\)
         =\(\frac{\sin A\cos B-\cos A\sin B}{\cos A\cos B+\sin A\sin B}\)
         Devide numerator and denominator by \(\cos A\cos B\) we get

\(\tan(A-B)=\frac{\tan A -\tan B}{1+\tan A\tan B}\)

Derive the formula of \(\cot(A+B)\)

\(\cot(A+B)=\frac{\cos(A+B)}{\sin(A+B)}\)
         =\(\frac{\cos A\cos B-\sin A\sin B}{\sin A\cos B+\cos A\sin B}\)
         
Divide numerator and denominator by \(\sin A\sin B\) we get

\(\cot(A+B)=\frac{\cot A \cot B -1}{\cot B+\cot A}\)

Derive the formula of \(\cot(A-B)\)

\(\cot(A-B)=\frac{\cos(A-B)}{\sin(A-B)}\)
         =\(\frac{\cos A\cos B+\sin A\sin B}{\sin A\cos B-\cos A\sin B}\)
        
Divide numerator and denominator by \(\sin A \sin B\) we get

\(\cot(A-B)=\frac{\cot A \cot B -1}{\cot B-\cot B}\)


Derive the formula of \(\tan(A-B)\)

\(\tan(A-B)=\frac{\sin(A-B)}{\cos(A-B)}\)
         =\(\frac{\sin A\cos B-\cos A\sin B}{\cos A\cos B+\sin A\sin B}\)
         
Divide numerator and denominator by \(\cos A\cos B\) we get

\(\tan(A+B+C)\)=\(\frac{\tan A +\tan (B+C)}{1-\tan A\tan (B+C)}\)
         =\(\frac{\tan A +\frac{\tan B +\tan C}{1-\tan B\tan C}}{1-\tan A \times \frac{\tan B +\tan C}{1-\tan B \tan C}}\)
  =\(\frac{\tan A -\tan A \tan B \tan C +\tan B + \tan C}{1-\tan B \tan C-\tan C \tan A-\tan A \tan B}\)
 

Formula:

\(\tan(A+B)=\frac{\tan A +\tan B}{1-\tan A\tan B}\)
\(\tan(A-B)=\frac{\tan A -\tan B}{1+\tan A\tan B}\)
\(\cot(A+B)=\frac{\cot A \cot B -1}{\cot B+\cot A}\)
\(\cot(A-B)=\frac{\cot A \cot B -1}{\cot B-\cot B}\)
\(\tan(A+B+C)=\frac{\tan A -\tan A \tan B \tan C +\tan B + \tan C}{1-\tan B \tan C-\tan C \tan A-\tan A \tan B}\)

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