Q1. On the application of 50 N force, if the work is done 600 J. What will be the displacement of the point of application of force?
Solve:
W=F \(\times\) d
W=work=600 J
F=force=50 N
d=displacement=?
600=50 \(\times\) d
\(\therefore\) d=\(\frac{600}{50}\)
=12 m
Q2. A body of mass 50 kg acquires 400 J of kinetic energy. Find the velocity of the body.
Solve:
\(E_k\)=\(\frac{1}{2}mv^{2}\)
\(E_k\)=kinetic energy=400 J
m=mass of the body=50 kg
400=\(\frac{1}{2} \times m \times v^{2}\)
or, 400=\(25 v^{2}\)
or, \(v^{2}\)=\(\frac{400}{25}\)=16
\(\therefore\) v=\(\pm\sqrt{16}\)
or v=\(\pm 4\) m/s
\(\therefore\) v=4 m/s
Q3. A stone of mass 100 kg was lifted to a height of 10 m. Find the potential energy, possessed by the body. (g=9.8 m/\(s^{2}\))
Solve:
\(E_p\)=mgh
m= mass of the stone=100 kg
h= height=10 m
g= gravitational force=9.8 m/\(s^{2}\)
\(E_p\)=potential energy=?
\(E_p\)=100 \(\times\) 9.8 \(\times\) 10
=9800.0
=9800 J