The electric potential and electric field intensity are two core concepts in electrostatics. While electric potential (\( V \)) is a scalar quantity that represents potential energy per unit charge, electric field intensity (\( \vec{E} \)) is a vector quantity that describes the force experienced per unit charge. They are closely related through a spatial rate of change.
Electric field intensity is defined as the negative gradient of electric potential. That is:
\( \vec{E} = -\nabla V \)
This means the electric field is oriented in the direction where the electric potential decreases most rapidly.
Consider a small test charge \( q \) moving through a displacement \( d\vec{x} \) in an electric field \( \vec{E} \). The infinitesimal work done by the electric field on the charge is:
\( dW = \vec{F} \cdot d\vec{x} = q \vec{E} \cdot d\vec{x} \)
From the definition of electric potential difference:
\( dV = \frac{dW}{q} = \vec{E} \cdot d\vec{x} \)
According to convention, the potential difference is taken as the negative of the work done by the electric field per unit charge.
\( dV = -\vec{E} \cdot d\vec{x} \)
If the field varies only along the x-direction:
\( E_x = -\frac{dV}{dx} \)
\[ \vec{E} = -\left( \frac{\partial V}{\partial x} \hat{i} + \frac{\partial V}{\partial y} \hat{j} + \frac{\partial V}{\partial z} \hat{k} \right) \]
This is compactly written as: \( \vec{E} = -\nabla V \)
In a graph of potential vs. position, the slope of the curve at any point gives the magnitude of the electric field at that point (with a negative sign). Steeper slopes indicate stronger fields.