Vector addition is a cornerstone of physics and mathematics, enabling us to combine quantities like forces, velocities, and displacements. Among the methods for adding vectors, the Triangle Law is one of the most intuitive and widely used. This article breaks down the triangle law, its applications, step-by-step procedures, and common pitfalls to help you ace exams and solve real-world problems.
The Triangle Law states that if two vectors are represented as two sides of a triangle taken in tip-to-tail order, the resultant vector is given by the third side of the triangle drawn from the starting point of the first vector to the endpoint of the second.
Formula: If vectors \( \vec{A} \) and \( \vec{B} \) form two sides of a triangle, the resultant \( \vec{R} \) is:
\( \vec{R} = \vec{A} + \vec{B} \)
Magnitude:
\(\mid\overrightarrow{R}\mid=\sqrt{A^{2}+B^{2}+2AB\cos\theta}\)
Direction:
\( \phi = \tan^{-1} \left( \frac{B\sin\theta}{A + B\cos\theta} \right) \)
Here, \( \theta \) is the angle between \( \vec{A} \) and \( \vec{B} \) when placed tip-to-tail.
Represent \( \vec{A} \) as an arrow with length proportional to its magnitude.
Example: A displacement of 4 units east.
Place the tail of \( \vec{B} \) at the tip of \( \vec{A} \).
Example: A displacement of 3 units north.
Connect the tail of \( \vec{A} \) to the tip of \( \vec{B} \).
\( \vec{R} \) represents the combined effect.
For \( \theta = 90^{\circ} \):
\( R = \sqrt{A^2 + B^2} \)
For general angles: Use cosine and sine rules.
Diagram: Two vectors \( \vec{A} \) and \( \vec{B} \) form a triangle, and \( \vec{R} \) is the closing side from the start of \( \vec{A} \) to the end of \( \vec{B} \).
Example: A boat moves north at 4 m/s in a river flowing east at 3 m/s. Resultant velocity = 5 m/s northeast.
Pro Tip: Always draw a vector diagram—it helps avoid mistakes.
A: Yes. Extend it to the polygon law by adding vectors tip-to-tail in sequence.
A: Triangle law adds vectors sequentially; parallelogram law adds from a common origin.
A: Add the negative vector: \( \vec{A} - \vec{B} = \vec{A} + (-\vec{B}) \)
Problem: A car moves 8 km east and then 6 km northwest. Find the resultant displacement.
Angle between east and northwest = \( \theta = 135^{\circ} \)
\( R = \sqrt{8^2 + 6^2 + 2 \cdot 8 \cdot 6 \cdot \cos(135^{\circ})} \)
Answer: \( R \approx 5.2 \) km